Examples: query, "exact match", wildcard*, wild?ard, wild*rd
Fuzzy search: cake~ (finds cakes, bake)
Term boost: "red velvet"^4, chocolate^2
Field grouping: tags:(+work -"fun-stuff")
Escaping: Escape characters +-&|!(){}[]^"~*?:\ with \, e.g. \+
Range search: properties.timestamp:[1587729413488 TO *] (inclusive), properties.title:{A TO Z}(excluding A and Z)
Combinations: chocolate AND vanilla, chocolate OR vanilla, (chocolate OR vanilla) NOT "vanilla pudding"
Field search: properties.title:"The Title" AND text
Unanswered
Write me a program that would automatically change all of these file names to look like the examples I gave

Prompt:
I have hundreds of files with a date naming pattern. Here are 5 example files: 1. "20220914230334" 2. "20220915212429" 3. "20220916113012" 4. "20220917113220" 5. "20220918113356". The first four numbers in each of the names represent the year, the next two represent the month, the two after that represent the day, and the other 6 are unneeded. For example, file 1 that I mentioned would translate to "September 14th, 2022", and file 2 would translate to "September 15th, 2022". Write me a program that would automatically change all of these file names to look like the examples I gave.

import os

# the path to the directory where the files are located
path = '/path/to/files/'

# get a list of all the files in the directory
files = os.listdir(path)

# loop through each file
for file in files:
 # split the file name and extension
 name, extension = os.path.splitext(file)

 # get the year, month, and day from the file name
 year = name[0:4]
 month = name[4:6]
 day = name[6:8]

 # create the new file name
 new_name = f"{year}-{month}-{day}{extension}"

 # rename the file
 os.rename(f"{path}/{file}", f"{path}/{new_name}")

print("Done!")
  
  
Posted one year ago
Edited one year ago
Rish
430 × 6 Administrator
Votes Newest

Answers

851 Views
0 Answers
one year ago
one year ago
Tags